32y^2-(44)=0

Solution for 32y^2-(44)=0 equation:

32y^2-(44)=0

a = 32; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·32·(-44)
Δ = 5632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5632}=\sqrt{256*22}=\sqrt{256}*\sqrt{22}=16\sqrt{22}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{22}}{2*32}=\frac{0-16\sqrt{22}}{64}
=-\frac{16\sqrt{22}}{64}
=-\frac{\sqrt{22}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{22}}{2*32}=\frac{0+16\sqrt{22}}{64}
=\frac{16\sqrt{22}}{64}
=\frac{\sqrt{22}}{4}
$